 # FizzBuzz In Python

Recently I started looking for a new role, a new developer role. During my interviews, I have come across a number of questions and coding challenges. For each of these challenges, I take my time, create the code. I then come home and revisit that challenge to write a better solution.

In this new solution I create it in a few different languages, just to challenge myself, but to also provide my solution to anyone who maybe looking for the solution the this quiz question.

For this challenge I take one of the common coding quizzes I've seen asked during an interview is the FizzBuzz code question.

## FizzBuzz

What is FizzBuzz? Simply put, its a challenge that will print one of 3 words when a number is divisible by a given number, and if not divisible it will output the number.

So, it seems common to give the following parameters:

1. Number range is 1 to 100
2. If the number is divisible by 3 then output Fizz
3. If the number is divisible by 5 then output Buzz
4. If the number is divisible by 3 and 5 then output Fizzbuzz
5. If the number is not divisible by the above values, output the value

### FizzBuzz in Python

Given the above parameters, here is my solution for this FizzBuzz challenge written in Python

``````def fizz_buzz(count):
found = False

for current_value in range(1, count+1):
output_string = ""

if current_value % 3 == 0:
output_string = "Fizz"
found = True

if current_value % 5 == 0:
output_string += "Buzz"
found = True

if found == False:
output_string = current_value

print(output_string)
found = False

fizz_buzz(100)``````