# FizzBuzz In Java

Recently I started looking for a new role, a new developer role. During my interviews, I have come across a number of questions and coding challenges. For each of these challenges, I take my time, create the code. I then come home and revisit that challenge to write a better solution.

Recently I started looking for a new role, a new developer role. During my interviews, I have come across a number of questions and coding challenges. For each of these challenges, I take my time, create the code. I then come home and revisit that challenge to write a better solution.

In this new solution I create it in a few different languages, just to challenge myself, but to also provide my solution to anyone who maybe looking for the solution the this quiz question.

For this challenge I take one of the common coding quizzes I've seen asked during an interview is the FizzBuzz code question.

## FizzBuzz

What is FizzBuzz? Simply put, its a challenge that will print one of 3 words when a number is divisible by a given number, and if not divisible it will output the number.

So, it seems common to give the following parameters:

1. Number range is 1 to 100
2. If the number is divisible by 3 then output Fizz
3. If the number is divisible by 5 then output Buzz
4. If the number is divisible by 3 and 5 then output Fizzbuzz
5. If the number is not divisible by the above values, output the value

### FizzBuzz in Java

Given the above parameters, here is my solution for this FizzBuzz challenge written in Java

``public class FizzBuzz {  	public static void main(String[] args) {  		boolean foundVal = false; 		 		int count; 		 		for(count = 1; count <= 100; count++) 		{ 			if (count%3 == 0) { 				System.out.print("Fizz");  				foundVal = true; 			} 			if (count%5 == 0) { 				System.out.print("Buzz");  				foundVal = true; 			} 			if (foundVal) System.out.println(""); 			if (!foundVal) System.out.println(count); 			 			foundVal = false; 			 		} 	}  }``

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